CSIS 111 Module Week 2 ASSIGNMENT INPUT OUTPUT

Description

The number of permutations of a set of n items taken r at a time is given by the following formulan!/r!(n−r)!: where n! is the factorial of n, r! is the factorial of r, and (n-r)! is the factorial of the result of n-r. The factorial of a number n can be solved using the following formula: n !=e−n nn √ 2 πn.
If there are 18 people in your class and you want to divide the class into programming teams of 3 members, you can compute the number of different teams that can be arranged using this formula (n!/r!(n−r)!).
Write a C++ program that determines the number of potential team arrangements. You will need to use the double type for this computation. Use the Lab Template you set-up last week, proper formatting, and appropriate comments in your code. The output must be labeled clearly and formatted neatly.
Submit C++ Programming Assignment 2 by 11:59 p.m. (ET) on Monday of Module/Week 2.
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CSIS 111 Week 2
CSIS 111 Assignment 2
The solution includes Visual Studio project, report, screenshots.
Attachments [Move over files to preview content of those files]
CSIS_111_Week_2.zip (19.18 MB)
CSIS111-Week-2-Screenshot-1.png
CSIS111-Week-2-Screenshot.png
Firstname_Lastname_Assignment2_Report.docx
Visual Studio Project
CSIS111Assignment2
.vs
CSIS111Assignment2
v16
.suo
Browse.VC.db
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CSIS111ASSIGNMENT2.ipch
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CSIS111ASSIGNMENT2.ipch
CSIS111Assignment2
CSIS111Assignment2.cpp
CSIS111Assignment2.vcxproj
CSIS111Assignment2.vcxproj.filters
CSIS111Assignment2.vcxproj.user
Debug
CSIS111A.7919bafb.tlog
CSIS111Assignment2.lastbuildstate
CSIS111Assignment2.exe.recipe
CSIS111Assignment2.ilk
CSIS111Assignment2.obj
vc142.idb
vc142.pdb
CSIS111Assignment2.sln
Debug
CSIS111Assignment2.exe
CSIS111Assignment2.pdb
Preview CSIS111Assignment2.cpp
//
— xxxxx xxxxxxxxx xx xx xxx xxxx�x xxxxxxx
//xxxx 111- xxxxxxxxxx 2
//
//xxxxxxx xxxxxxxxxx
#xxxxxx _xxx_xxxx_xxxxxxx
#include
#include
#include
using namespace std; //Global declarations: Constants and type definitions only — no variables
//xxxxxxxx xxxxxxxxxx
xxxxxx xxxxxxxxx(xxx x) {
xxxxxx xxx(x_x, -x) * xxx(x, x)* xxxx(2 * x_xx * x);
}
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